Here if Statement is true and if statement executes left to right. Since its AND operator so all the condition should be check until it finds any false statement. Initially y = 10 In 1st condition: y++>9 which is true and y become 11 in next use. In 2nd condition: y++!=10 which is also true and y become 12 in next use In 3rd condition: y++>11 which is also true and y become 13 in next use After that printf statement will execute and print y = 13

As the value of num is decremented(--num) and again incremented(++num) and hence no change in num and it remains 0 only causing infinite loop.

First of all for loop have no braces so for loop on have only next line in its body.
for( ; digit <= 9; )
digit++;
After completing for loop digit = 10;
next statement digit *= 2; i.e digit = digit * 2 = 20;
next statement digit--; i.e 20-- => 19
So final value of digit is 19

As the first option is matching, the cases are evaluated till the break statement is encountered or end of switch statement is encountered.

Syntax: continue ;

Causes control to pass to the end of the innermost enclosing while, do, or for statement, at that point the loop continuation condition is re-evaluated. Example:

Condition if(c[a]%2 == 1) forces only odd numbers to add in the sum.

Since the condition is always true it will go to infinite loop.

In for loop the three statements parts are separated by two semicolons which are missing here.

the if is conditional and it checks for expression whether it is zero or non-zero so it doesn't print any data it is clear and it is clearly seen that there is not a single syntax error therefore no complier error.
After compling the program will be executed but there is not a single printf statement so it is executed but will not give any output.

Decrement operator in for loop statement are executed until the condition is true.
So it is executed till "a" not equal to zero and printf statement inside for loop print a value of "a"

Here if statement is executed since we know that printf() function return the number of character print.
Here printf("%d", i) return 2 because it print 1 and newline i.e 2.
And, printf("%d', j) return 3 because it print -1 and newline i.e number of character is 3.
Therefore if statement look like if(2<3) yes its true.
So if statement will execute. And answer is 1 -1 1.

for loop can be initialized outside of the loop. Since until -1 value of i remain a non-zero value and hence the condition is true up to -1. But when i is further increases its value becomes 0 and condition becomes false and loop stops there.

Note:In C any non-zero value(positive or negative) evaluates to true and only zero value is evaluates to false.

Due to semicolon(;) at the end of the for loop, after 10 iterations for loop will be terminated and the result will be 10.

Here if condition evaluates to true as a non-zero value i.e 5 is assigned to a.
So the value of a = 5 and after increment value of b = 6.
In printf statement due to pre-increment of a value of a printed will be 6 and due to post-increment of b value of b printed will be 6 and not 7.

'If' statement only true when value of 's' is less then 4

As the value of variable value is zero so, it evaluates to false in the if condition.

Expression value2%5 is equal to 0 and this value assigned to value1.
Therefore if condition reduces to if(0) so it fails.
Therefore body of if will not be executed i.e num = 5 will not be assigned.
So at printf num = 100 , value1 = 0 and value2 = 100.

compiler error switch expression is not integral. switch statement cannot work on float value.