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Class 11 Chemistry
Redox Reactions
Quiz 1
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The oxidation number of Cl in Cl Ois
0%
+ 7
0%
+ 5
0%
+ 3
0%
– 7
Explanation
+ 7
What is known as Autooxidation?
0%
Formation of HO by the oxidation of HO
0%
Formation of HO by the oxidation of HO.
0%
Both (1) and (2) are true
0%
None of the above
Explanation
Formation of HO by the oxidation of HO.
The tendency of an electrode to lose electrons is known as
0%
Electrode Potential
0%
Reduction Potential
0%
Oxidation Potential
0%
E. M. F.
Explanation
Oxidation Potential
If equal volumes of 1M KMnO and 1M KCrO solutions are allowed to oxidize Fe in acidic medium. The amount of iron oxidized will be:
0%
More with KMnO
0%
More with K
0%
Equal with both oxidising agents
0%
Cannot be determined
Explanation
More with K
Which of the following processes does not involve either oxidation or reduction?
0%
Formation of slaked lime from quick lime
0%
Heating Mercuric Oxide
0%
Formation of Manganese Chloride from Manganese oxide
0%
Formation of Zinc from Zinc blende
Explanation
Formation of slaked lime from quick lime
One mole of NH loses ten moles of electrons to form a new compound A. Assuming that all the nitrogen appears in the new compound, what is the oxidation state of nitrogen in A? (There is no change in the oxidation state of hydrogen. )
0%
-1
0%
-3
0%
+3
0%
+5
Explanation
+3
How many millilitres of5 M H SO are needed to dissolve5 g of copper(II)carbonate?
0%
6. 01
0%
4. 5
0%
8. 1
0%
11. 1
Explanation
8. 1
The oxidation state of Cr in Cr (CO) is
0%
0
0%
2
0%
2
0%
6
Explanation
0
Which of the following processes does not involve oxidation of iron?
0%
Formation of Fe(CO)
0%
Liberation of H
0%
Rusting of iron sheets.
0%
Decolourisation of blue CuSO
Explanation
Formation of Fe(CO)
The number of moles of KMnO reduced by one mole of KI in alkaline medium is
0%
One
0%
Two
0%
Five
0%
One fifth.
Explanation
Two
Which of the following reactions does not involve either oxidation or reduction?
0%
VO→ VO
0%
Na → Na
0%
CrO→ CrO
0%
Zn→Zn
Explanation
CrO→ CrO
KMnO reacts with oxalic acid according to the equation 2MnO + 5CO + 16H+ → 2Mn +10CO+ 8H O Here 20 mL of 0.1 M KMnO is equivalent to
0%
50 mL of 0. 5 M CHO
0%
20 mL of 0. 1 M CHO
0%
20 mL of 0. 5 M CHO
0%
50 mL of 0. 1 M CHO
Explanation
50 mL of 0. 1 M CHO
One mole of NH
0%
-1
0%
-3
0%
+3
0%
+5
Explanation
+3
What is n-factor?
0%
Equal to product of Number of moles of electrons when Lost or gained by one mole of reductant or oxidant
0%
When Number of moles of electrons Lost or gained by one mole of reductant or oxidant is not same.
0%
Equal to Number of moles of electrons Lost or gained by one mole of reductant or oxidant
0%
None of the above
Explanation
Equal to Number of moles of electrons Lost or gained by one mole of reductant or oxidant.
Explanation:
For redox reaction it is considered as change in their oxidation number or change in their reduction number in both side of a chemical reaction.
The oxidation number of Mn is maximum in
0%
MnO
2
0%
K
2
MnO
4
0%
Mn
3
O
4
0%
KMnO
4
.
Explanation
KMnO
4
.
Explanation:
The electronic configuration of Mn is:
Mn(25) = [Ar]3d
5
4s
2
, 4p
0
In excited state, it can lose its all 7 electrons.
Hence, maximum oxidation sate exhibited by Mn is +7 which is in KMnO
4
.
The oxidation process involves
0%
Increase in oxidation number
0%
Decrease in oxidation number
0%
No change in oxidation number
0%
none of the above
Explanation
Increase in oxidation number
Metals generally react with dilute acids to produce hydrogen gas. Which one of the following metals does not react with dilute hydrochloric acid?
0%
Copper
0%
Magnesium
0%
Iron
0%
Silver
Explanation
Magnesium
The oxidation number of Xe in BaXeO is
0%
8
0%
6
0%
4
0%
10
Explanation
10
The colourless solution of silver nitrate slowly turns blue on adding copper chips to it because of
0%
Dissolution of Copper
0%
Oxidation of Ag→ Ag
0%
Reduction of Cu ions
0%
Oxidation of Cu atoms.
Explanation
Oxidation of Cu atoms.
A standard reduction electrode potentials of four metals are A = -250 V, B = -140 V, C = -126 V, D = -402 V The metal that displaces A from its aqueous solution is:
0%
A
0%
B
0%
C
0%
D
Explanation
D
0 h : 0 m : 1 s
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