Explanation: In the diagram shown above, the tubes are individually finned in the form of discs on every tubes separately. Hence the given fin is Individually finned tubes.

Explanation: In the diagram shown above, the tubes are finned in the form of plates attached to each and every tube. Hence the given fin is Flat (continuous) fins.

Explanation: As in the diagram, we observe series of discs with wavy nature on each, shown by the wave inside the discs. Hence the given fin is Wavy Disc.

Explanation: In the left part of the diagram we observe cut on the fins which runs along the axis of the tube. Hence, this type of fin is usually used to increase the turbulence to a greater extent.

Explanation: The diagram on the left shows no cut and the right-side diagram shows a helical pattern, hence the given fin is a Helical one.

Explanation: The diagram show broken bits of plates attached to the surface of the tube usually by welding it onto it, also the diagram does not show any helical patterns. Hence these types of fins are called studded fins.

Explanation: The figure represents a double helical fin as is clear from the fact that we observe two helixes running parallel to each other. These types of fins are one of the most commonly used in industry.

Explanation: The fins in the given diagram are annular type or disc fins attached to the tubes parallel to each other. Usually the outside fluid runs perpendicular to the tubes and parallel to the fins which facilitate high heat transfer rate.

Explanation: As in the diagram, we observe Helixes with wavy nature on each, shown by the wave inside the helix, hence these fins are called wavy helical.

Explanation: The given helix is called serrated fins as the surface of the fin/ the extreme edges are serrated and hence it looks somewhat similar to fully cut on helix.

Explanation: The utility of fin in dissipating a given quantity of heat is generally assessed on the basis of the fin’s efficiency in increasing the heat transfer coefficient and its effectiveness.

Hence the value is =(πDi-4xt+4x2xLfin)xL=\(\frac{(3.14X20-4X5+4X2X10)x1}{1000}\)=0.123m2.

Hence the value is = (\(\frac{π}{4}\)(Do2-Di2))- 4xtxLfin=\(\frac{3.14}{4}\)x(402-202)-4x5x10=742mm2.