Q.1.
Determine the relationship between log-antilog method.
- a) lnVx×lnVy = ln(Vx+Vy)
- b) lnVx / lnVy = ln(Vx-Vy)
- c) lnVx -lnVy = ln(Vx/Vy)
- d) lnVx+ lnVy = ln(Vx×Vy)
Q.2.
Which circuit allows to double the frequency?
- a) Frequency doubler
- b) Square doubler
- c) Double multiplier
- d) All of the mentioned
Q.3.
Compute the output of frequency doubler. If the inputs Vx = Vsinωt and Vy = Vsin(ωt+θ) are applied to a four quadrant multiplier?
- a) Vo= { Vx×Vy× [cosθ-(cosθ×cos2ωt)+(sinθ×sin2ωt)]}/ Vref
- b) Vo= { Vx×Vy× [cosθ-(cosθ×cos2ωt)+(sinθ×sin2ωt)]}/ 2
- c) Vo= { Vx×Vy× [cosθ-(cosθ×cos2ωt)+(sinθ×sin2ωt)]}/(2×Vref)
- d) Vo= – { Vx×Vy× [cosθ-(cosθ×cos2ωt)+(sinθ×sin2ωt)]}/(2×Vref)
Q.4.
How to remove the dc term produced along with the output in frequency doubler?
- a) Use a capacitor between load and output terminal
- b) Use a resistor between load and output terminal
- c) Use a Inductor between load and output terminal
- d) Use a potentiometer between load and output terminal
Q.5.
Find the voltage range at which the multiplier can be used as a squarer circuit?
- a) 0 – Vin
- b) Vref – Vin
- c) 0 – Vref
- d) All of the mentioned
Q.6.
Calculate the output voltage of a squarer circuit, if it input voltage is 3.5v. Assume Vref = 9.67v.
- a) 2.86v
- b) 1.27v
- c) 10v
- d) 4.3v
Q.7.
Which circuit can be used to take square root of a signal?
- a) Divider circuit
- b) Multiplier circuit
- c) Squarer circuit
- d) None of the mentioned
Q.8.
Find the output voltage of squarer circuit?
- a) Vo = √( Vref/|Vin|)
- b) Vo = √( Vref×|Vin|)
- c) Vo = √( Vref2×|Vin|)
- d) Vo = √( Vref×|Vin|2)
Q.9.
Find the current, IL flowing in the circuit given below
- a) IL = 1.777mA
- b) IL = 1.048mA
- c) IL = 1.871mA
- d) None of the mentioned
Q.10.
A square root circuit build from multiplier is given an input voltage of 11.5v. Find its corresponding output voltage?
- a) 11v
- b) 15v
- c) 13v
- d) Cannot be determined