The reaction is example of SN1 reaction Answer: (d)

The reaction is an example of electrophilic aromatic substitution. Although both OCH3 and CH3 groups are o,p- directing the OCH3 group dominates. Product (b) is favoured because the new group (Br) experience least hindrance Answer: (b)

Molecules having higher molecular weight and less branching have higher boiling point Answer: (b)

Answer:(d)

In case of unsymmetrical ethers, the site of cleavage depends on the nature of alkyl group CH3-O-C2H5 + HI → CH3I + C2H5OH [ At 373K] The alkyl halide is formed the smaller alkyl group. However, in case of tertiary alkyl ether following reaction occurs CH3-OC(CH3)3 + HI → (CH3)C-I + CH3OH The alkyl halide is formed from the tertiary alkyl group and the cleavage of such theirs occurs by SN2 mechanism as the product is controlled by the formation of more stable intermediate tertiary carbocation from protonated ether Answer: (a)

It is Willamson's synthesis. It involves the nucleophilic attack of alkoxide ion on alkyl halide according to SN2 mechanism. In order to prepare methyl tertiary butyl ether , we must use methyl halide ( primary) and sodium ethoxide and t-alkyl halide because the latter undergoes elimination reaction rather than substitution Answer: (c)

Writing the structure Thus option(d) is primary halide Answer: (d)

Compound Y must give iodoform test. Further since Y is obtained by the oxidation of X which must be an alcohol ( CH3CH2OH and thus Y is CH3CHO Answer:(a)

Maximum enol content is in structure (b) because here the enol form is stabilized by H-bonding Answer: (b)

Ethanol on dehydration forms diethyl ether Answer: (c)

Chloropicrin is nitrochloroform. It is obtained by the nitration of chloroform with Nitric acid. Chloropicrin is liquid, poisonous and used as insecticide and in war gas HCCl3 + HNO3 → O2NCCl3 Answer: (d)

CN- is a strong base and since the substrate is tert-halide, it mainly undergoes elimination reaction forming alkene(A). In presence of dil. H2SO4 alkenes undergo hydration in Markovnikov's way. Answer:(b)

Heavy metal ions, particularly Ag+ catalyse SN1 reaction because of presence of empty orbital Answer: (b)

Carbonyl compounds undergo nucleophilic addition Answer: (b)

Answer: (a)

In (a), due to similar charges ( two positive charges) on adjacent atom, the structure is expected to be least stable Answer:(a)

Stability of structure depends on (i) Number of π-bonds ∝ resonance energy ∝ stability (ii) Contributing structures should be such that negative charge resides on an electronegative element and positive on an electropositive element (iii) like charges should not reside on atoms closed to each other and unlike charges should not be widely separated. Thus order of stability in option (b) is correct Answer: (b)

RmgX + H2O → RH + Mg(OH)X Answer: (d)

The incoming nucleophile can attack from any side of carbocation leading to formation of racemic mixture Answer: (b)

Answer:(c)

Answer: (a)

Methyl halides are most reactive towards SN2 reactions. Order of reactivity towards SN2 reaction is CH3-X > 1o > 2o > 3o > Answer: (a)

Two position isomers are possible Answer: (b)

Only diethyl ketone CH3CH2COCH2CH3 does not contain the group CH3CO- or CH3OH and hence does not give iodoform test Answer:(c)

Answer: (d)

In air ethanol gets oxidised to acetic acid Answer : (b)

Glycerine contains three -OH groups out of which two are primary and one is secondary Answer : (d)

In presence of Conce. H2SO4 reaction Produce Diethyl ether 2C2H5OH → C2-O-C2H5 + H2O Answer : (c)

Answer : (d)

In Victor Meyer's test, blue colour salt is given by secondary alcohol. It means compound B must be a secondary alcohol Only aldehydes with Grignard reagent yield secondary alcohols. Aldehyde should have one carbon less than secondary alcohol since Grignard reagent contain methyl group. These conditions are satisfied by acetaldehyde and iso-propyl alcohol Answer : (c)