NEET Chemistry MCQ - Compounds Containing Nitrogen Mcq Neet Chemistry - Quiz-5 Solution

Q.1.

Attacking species in nitration of benzene, which of the following is intermediate?

20%
c) C6H5NH - NHC6H5
20%
a) C6H5 - N = N - C6H5
60%
b) C6H5 - N = O
0%
d)

Explanation

Q.2.

on Q123) The IUPAC name of following compound is

0%
a) 2-cyno-3methyl hexane
80%
b) 2,4-dimentyl pentane nitrile
20%
c) 2-dimethyl-4-cyanopentane
0%
d) 2-cyno-3-methyl hexane

Explanation

Q.3.

Aniline when treated with conc. HNO3 gives

17%
a) Nitrobenzene
50%
b) p-phenylenediamine
17%
c) p-benzoquinone
17%
d) m-nitroaniline

Explanation

Q.4.

In the nitration of benzene with a mixture of concentrated nitric acid and concentrated sulphuric acid, the active species involved is

40%
a) Nitrate ion
0%
b) Nitrite ion
40%
c) Nitronium ion
20%
d) Nitric oxide

Explanation

Q.5.

on Q126) Identify X in the sequence.

25%
a) (CH3)3N
75%
b) CH3-CH2-CH2-NH2
0%
c) CH3-NH-CH2-CH3
0%
d) none of the above

Explanation

Q.6.

The correct order of increasing basicity in aqueous solution is

25%
a) C6H5NH2 < NH3 < C6H5NH2 <(C2H5)3N<(C2H5)2NH
75%
b)NH3 < C6H5NH2 < (C2H5)2NH < C2H5NH2 < (C2H5)3N
0%
c) C6H5NH2 < NH3 < (C2H5)3N < C6H5NH2 < (C2H5)2NH
0%
d) None of the above

Explanation

Q.7.

Which of the following statement about primary amines is false?

20%
a) Alkyamines are stronger base than aryl amines
60%
b) Alkylamines reacts with nitrous acid to produce alcohols
20%
c) Arylamines react with nitrous acid to produce phenols
0%
d) Alkylamines are stronger base than ammonia

Explanation

Q.8.

Reaction of aniline with benzaldehyde is a .... .... reaction

50%
a) Addition
0%
b) Substitution
50%
c) Condensation
0%
d) None of these

Explanation

Q.9.

Amongst the following, the most basic compound is

25%
a) Aniline
0%
b) Acetanilide
25%
c) Benzylamine
50%
d) p-nitroaniline

Explanation

Q.10.

on Q131)What is A infollowing reaction

25%
a) RCONH2
0%
b) RCOOH
25%
c) RNH2
50%
d) R-NCO

Explanation

Q.11.

Reduction of nitrobenzene in the presence of Zn/NH4Cl gives

0%
a) Aniline
25%
b) Azobenzene
50%
c) Hydraazobenzene
25%
d) N-phenylhydroxylamine

Explanation

Q.12.

on Q133) Match the compounds in List I with the appropriate test that will be answered by each one of them in List II from the combinations shown:

I. Propyne	A. Reduces Fehling's solution
II. Ethyl benzoate	B. Forms a precipitate with AgNO₃ in ethanol
III. Acetaldehyde	C. Insoluble in water but dissolveds in aqueous NaOH solution upon heating
IV. Aniline	D. Dissolves in dilute HCl in the cold and is reprecipitated by the addition of alkali

50%
a) I - B, II - C, III - A, IV - D
0%
b) I - A, II - D, III - B, IV - C
50%
c) I - D, II - B, III - C, IV - A
0%
d) I - A, II - D, III - C , IV - B

Explanation

Q.13.

The active species produced in Hofmann's bromide reaction is

0%
a) Br2
50%
b) OBr-
25%
c) OBr2
25%
d) Br-

Explanation

Q.14.

Nitrosoamines ( R2N - N = O) are insoluble in water. On heating with conc. H2SO4, they give secondary amines. The reaction is called

0%
a) Fries reaction
0%
b) Perkin reaction
75%
c) Liebermann nitroso reaction
25%
d) Etard reaction

Explanation

Q.15.

Assertion: In strongly acidic medium, aniline becomes less reactive towards electrophilic reagent Reason: - NH2 group is o- and p- directing

25%
a) both the assertion and reason are true and reason explains the assertion
75%
b) both the assertion and reason are true but reason does not explain the assertion.
0%
c) assertion is true but reason is false
0%
d) assertion is false but reason is true.

Explanation

Q.16.

Dry test can be used to distingusish between

0%
a) Methyl amine and ethyl amine
25%
b) Urea and acetamide
25%
c) Ethyl amine and aniline
50%
d) Ethyl amine and acetamide

Explanation

Q.17.

A positive carbylamine test is given by ... ...[ IIT 1999 ]

0%
a) N, N-dimethylaniline
25%
b) 2,4-dimethylaniline
0%
c) N-methyl-o-methylamine
75%
d) p-methyl benzylamine

Explanation

Q.18.

Ketones and 1° amines react to form

25%
a) amides
25%
b) anils
25%
c) urea
25%
d) oximes

Explanation

Q.19.

Acetoneoxime on catalytic hydrogenation gives [ PET (MP) 1993]

25%
a) 1-propanamine
0%
b) isopropylamine
50%
c) ethyl methyl amine
25%
d) CH4 and ethanamine

Explanation

Q.20.

Aniline, chloroform and alc.KOH on heating give

25%
a) phenyl isocyanide
25%
b) phenol
0%
c) phenyl cyanide
50%
d) chlorobenzene

Explanation

Q.21.

Amongst the compounds given, the one that would form a brilliant coloured dye on treatment with NaNO2 in dil. HCl followed by addition to an alkaline solution of β-naphthol is [ IIT 2011]

50%
a)
25%
b)
0%
c)
25%
d)

Explanation

Q.22.

A compound A has a molecular formula C7H7NO. On treatment with Br2 and KOH, A gives an amine B which gives carbylamine test, B upon diazotisation and coupling with phenol gives an azo dye. A can be

25%
a) C6H5NO2
50%
b) C6H5CONH2
25%
c) o-, m- and p-C6H4(NH2)CHO
0%
d) none of above

Explanation

Q.23.

Which of the following reactions does not yield an amine?

0%
a) R-X + NH3 →
0%
b)
100%
c)
0%
d)

Explanation

Q.24.

on Q146) Identify X in the reaction

50%
a)
50%
b)
0%
c)
0%
d)

Explanation

Q.25.

When nitrobenzene is treated with Br2 in presence of FeBr3, the major product formed in m-bromonitrobenzene. Statements which are related to obtain the m-isomer are ... [ IIT 1992]

33%
a) the relative electron density on meta carbon is more than that of ortho and para positions
67%
b) loss of aromaticity when Br+ attacks at the ortho and para positions and not at meta position
0%
c) easier loss of H+ to regain aromaticity from the meta position than from ortho and para positions
0%
d) none of the above