Q.1.
on Q302) In sickle cell Hb:
-
0%
a) Glutamic acid is substituted by valine in α – chain.
-
0%
b) Glutamate is substituted by valine in α – chain.
-
100%
c) Valine is substituted by glutamic acid in β – chain.
-
0%
d) Glutamic acid is substituted by valine in β– chain.
Q.2.
on Q303) In the dihybrid genotypic ration 1: 2: 1: 2: 4: 2: 1: 2: 1; the numerical ‘4’ stands for the following type of genotype:
-
0%
a) Homozygous/pure form.
-
0%
b) Monohybrid forms.
-
0%
c) Heterozygous/Impure forms.
-
0%
d) Trihybrid form for two genes.
Q.3.
on Q304) The total number and types of gametes produced by a heterogeneous genotype are as follows: What will be the distance between genes ‘a’ and ‘b’?
-
0%
a) 16cM.
-
50%
b) 20cM.
-
50%
c) 32cM.
-
0%
d) 80cM.
Q.4.
on Q305) When is the sex of an offspring decided?
-
0%
a) At ovulation
-
0%
b) During meiosis
-
0%
c) During cleavage
-
0%
d) At fertilization
Q.5.
on Q306) Colour blindness is caused due to
-
0%
a) deficiency of vitamin C
-
100%
b) sex-linked abnormality
-
0%
c) absence of rods in retina
-
0%
d) absence of visual purple in retina
Q.6.
on Q307) It is unfortunate that in our society women are blamed for producing female children and have been obstracised and ill-treated because:
-
0%
a) The sex is determined by the type of sperm fertilizing the egg.
-
0%
b) The sex is determined by the type of egg fertilizing the sperm.
-
0%
c) the sex is determined by the hormones produced by the foetus
-
0%
d) the sex is determined by the God's Will
Q.7.
on Q308) A man whose father was colour-blind marries a woman, who has a colour-blind mother and normal father. What percentage of male children of this couple will be coloured?
-
0%
a) 25%
-
0%
b) 0%
-
0%
c) 50%
-
0%
d) 75%
Q.8.
on Q309) A diagrammatic representation of karyotype of a species is referred to as its
-
0%
a) idiogram
-
0%
b) hologram
-
0%
c) karyogram
-
0%
d) monogram.
Explanation
Q.9.
on Q310) Gene which suppresses other gene's activity but does not lie on the same locus is called as
-
0%
a) epistatic
-
0%
b) supplementary
-
0%
c) hypostatic
-
0%
d) co dominant
Q.10.
on Q311) Number of linkage groups in Ophioglossum:
-
0%
a) 1260.
-
0%
b) 630.
-
0%
c) 42.
-
0%
d) 800.
Q.11.
on Q312) What is the means of segregation in Law of segregation?
-
0%
a) Allelic separation
-
0%
b) Chromosomal separation
-
0%
c) Crossing over
-
0%
d) Linkage
Q.12.
on Q313) Mendel’s success was largely due to his choice of the garden pea plant for his experiments. The advantages of using this plant included: I. Presence of easily observable contrasting traits for many characters. II. It was possible to control pollination [and hence mating] between different pea plants. III. A large number of seeds could be produced and statistical analysis was therefore more accurate. IV. A long generation time means expression of all traits completely. V. Many observable traits were controlled by single genes.
-
0%
a) Only I, II and III
-
0%
b) Only I, II and V
-
0%
c) Only I, II, III and V
-
0%
d) Only II, III, IV and V
Q.13.
on Q314) Among human males _______ chromosome is present but its counterpart is _____ and called ______ chromosome.
-
0%
a) Y, bigger, Z
-
0%
b) X, smaller, Z
-
0%
c) X, smaller, Y
-
0%
d) Z, bigger, X
Q.14.
on Q315) If a normal female has a sickle cell anaemic child what can be the probable genotype of that gene in that female?
-
0%
a) AA
-
0%
b) aa
-
0%
c) Aa
-
0%
d) both (1) and (3)
Q.15.
on Q316) Colour Blindness is ------- due to defect in either----- or---- ------ of eye.
-
0%
a) Sex-linked recessive disorder, red, orange rods
-
0%
b) Sex-linked dominant disorder, red, green rods
-
0%
c) Sex-linked dominant disorder, red orange cones
-
0%
d) Sex-linked recessive disorder, red , green cones
Q.16.
on Q317) Eye colour in humans is controlled by a single pair of gene where B i.e. brown is dominant to b i.e. blue. What will be the proportion of eye colour of their offspring of a brown eyed man who marries a blue eyed lady?
-
0%
a) 3:1
-
0%
b) 2:3
-
0%
c) 1:1
-
0%
d) 1:2
Q.17.
on Q318) In a dihybrid cross, if you get 9: 3: 3: 1 ratio it denotes that:
-
0%
a) The alleles of two genes are interacting with each other.
-
0%
b) It is a multigenic inheritance.
-
0%
c) It is a case of multiple allelism.
-
0%
d) The alleles of two genes are separately independent.
Q.18.
on Q319) Drosophila melanogaster is found to be very suitable for genetic studies because: (i) They could be grown in simple synthetic medium in the laboratory. (ii) They complete their life cycle in about 140 days. (iii) A single mating could produce a large number of progenies. (iv) Male and female are clearly distinguishable. (v) It has very few hereditary variations that could be seen with high power microscope. Select the number of correct statements:
-
0%
a) 5
-
0%
b) 4
-
0%
c) 2
-
0%
d) 3
Q.19.
on Q320) The point mutations A to G, C to T, C to G and T to A in DNA are
-
0%
a) Transition, transition, transversion and transversion respectively.
-
0%
b) Transition, transversion, transition and transversion respectively.
-
0%
c) Transversion, transversion, transition and transition respectively.
-
0%
d) All four are transition.
Q.20.
on Q321) Mendelism is genetics of
-
0%
a) Haploids
-
0%
b) Diploids
-
0%
c) Prokaryotes
-
0%
d) All the above
Q.21.
on Q322) If distance between gene on chromosome in more , then gene shows :-
-
0%
a) Less Linkag
-
0%
b) strong linkage
-
0%
c) weak linkage
-
0%
d) incomplete linkage
Q.22.
on Q323) Punnet square is used to know
-
0%
a) outcome of a cross
-
0%
b) probable result of a cross
-
0%
c) Types of gametes
-
0%
d) Number of gametes
Q.23.
on Q324) State the cause of Philadelphia syndrome
-
0%
a) Deletion from the long arm of chromosome number 20
-
0%
b) Duplication in long arm of chromosome number 20
-
0%
c) Deletion from the long arm of chromosome number 22
-
0%
d) Deletion from the short arm of chromosome number 22
Q.24.
on Q325) Match the following
| Column I | Column II |
| Co- dominance | a. More then two optional forms of a gene |
| Polygenic inheritance | b. Multiple effect of a single gene |
| Multiple alleles | c. Quantitative inheritance |
| Pleiotropism | d. Both gene express their expression independently |
-
0%
a) (1 - d) (2 - c) (3 - a) (4 - b)
-
0%
b) (1 - a) (2 - c) (3 - b) (4 - d)
-
0%
c) (1 - d) (2 - a) (3 - c) (4 - b)
-
0%
d) (1 - a) (2 - b) (3 - d) (4 - c)
Q.25.
on Q331) If an individual does not breed true for its characters, it is called
-
0%
a) homozygote
-
0%
b) allelomorph
-
0%
c) hybrid
-
0%
d) ecotype
Q.26.
on Q332) A test cross is done to find out:
-
0%
a) Fitness of an organism
-
0%
b) Genotype of a plant expressing dominant phenotype.
-
0%
c) The suitable parents for a Mendelian Cross
-
0%
d) The hidden genotypic ratio of F2 phenotypes.
Q.27.
on Q333) A disease caused by an autosomal primary non-disjunction is
-
0%
a) Down's syndrome
-
0%
b) Klinefelter’s syndrome
-
0%
c) Turner's syndrome
-
0%
d) Sickle-cell anaemia
Q.28.
on Q334) A common test to find the genotype or hybrid is by:
-
0%
a) crossing of one F2 progeny with male parent
-
0%
b) crossing of one F2 progeny with female parent
-
0%
c) studying the sexual behaviour of F1 progenies
-
0%
d) crossing of one F1 progeny with male parent
Q.29.
on Q335) Study the pedigree chart of a family showing the inheritance of Myotonic dystrophy The trait under study is
-
0%
a) dominant X-linked
-
0%
b) recessive X-linked
-
0%
c) autosomal dominant
-
0%
d) recessive Y-linked.
Q.30.
on Q336) Sickle cell anaemia is example of
-
0%
a) sex-linked inheritance
-
0%
b) deficiency disease
-
0%
c) autosomal heritable disease
-
0%
d) infectious disease
Q.31.
on Q337) Which among the following type of point mutation occurs in Sickle cell anaemia?
-
0%
a) Transition and Non- sense.
-
0%
b) Transversion and mis-sense.
-
0%
c) Transversion and silent.
-
0%
d) Transition and mis-sense.
Q.32.
on Q338) An organism with two copies of the same allele is:
-
0%
a) Homozygous for that trait
-
0%
b) Homologous for the allele
-
0%
c) Heterozygous for that trait
-
0%
d) Heterologous for the allele
Q.33.
on Q339) In chickens, gene R produces a rose-shaped comb, gene r produces a single comb, gene P produces pea-shaped comb and gene p produces a single comb. When P and R are both present in the genotype, the comb is walnut shaped. Two chickens with genotype RrPp are intercrossed. What will be the ratio of Walnut shaped, Rose shaped, Pea shaped and single comb progeny respectively:
-
0%
a) 3 : 1 : 1 : 3
-
0%
b) 1 : 1: 1 : 1
-
0%
c) 9 : 3 : 3 : 1
-
0%
d) 12 : 3 : 4
Q.34.
on Q340) Which of the following genotypes could cause Sickle cell anaemia?
-
0%
a) HbB + HbA
-
0%
b) HbA+ HbA
-
0%
c) HbB + HbB
-
0%
d) Both ‘A’ and ‘C’.
Q.35.
on Q341) If two parents with AaBBccdd and aaBbccdd were crossed. What is the probability of getting following genotypes AaBbccdd and AABbccdd?
-
0%
a) 1/4, 0
-
0%
b) 0, 1/2
-
0%
c) 1/2, 1/4
-
0%
d) 0, 0
Q.36.
on Q342) Mendel’s experimental material was:
-
0%
a) Pisum sativum.
-
0%
b) Lathryus odoratus.
-
0%
c) Oryza sativa.
-
0%
d) Mirabilis jalapa.
Q.37.
on Q343) Linked genes may be separated by the process of
-
0%
a) gene mutation
-
0%
b) segregation
-
0%
c) crossing over
-
0%
d) polyploidy
Q.38.
on Q344) In a monohybrid cross F1 progeny resemble neither of the parents. What would be true in this case?
-
0%
a) The parental traits would not appear in any of the F2 -progenies
-
0%
b) The F2 phenotypic ratio will be different from the F2 genotypic ratio
-
0%
c) It could be a case of either incomplete dominance or co-dominance
-
0%
d) The F2 genotypic ratio will be similar to any Mendelian monohybrid cross
Q.39.
on Q345) Which one of the following is an example of polygenic inheritance?
-
0%
a) Flower colour in Mirabilis jalapa
-
0%
b) Production of male honey bee
-
0%
c) Pod shape in garden pea
-
0%
d) Skin colour in humans
Q.40.
on Q346) In rabbits, the gene for grey fur (G) is dominant over that for black fur (g). In a litter, if 50% rabbits are grey, then the possible parental cross combination is
-
0%
a) GG × Gg
-
0%
b) GG × GG
-
0%
c) gg × gg
-
0%
d) Gg × gg.
Q.41.
on Q347) Genes which code for a pair of contrasting traits are known as
-
0%
a) Factors
-
0%
b) Alleles
-
0%
c) Linked genes
-
0%
d) Lethal genes
Q.42.
on Q348) A man of blood group A marries a woman of AB blood group. Which type of progeny would indicate that man is heterozygous A?
-
0%
a) AB
-
0%
b) A
-
0%
c) O
-
0%
d) B
Q.43.
on Q349) Which among the following groups of genotype in Drosophila are recombinant genotypes?
-
0%
a)
-
0%
b)
-
0%
c)
-
0%
d)
Q.44.
on Q350) Which among the following genotype is representing Down syndrome?
-
0%
a) 44A + XXY.
-
0%
b) 45 + XX.
-
0%
c) 43A + XY.
-
0%
d) 44A + XY.
Q.45.
on Q351) A mutation that affects more than one type of phenotype is known as
-
0%
a) Pleiotropic mutation.
-
0%
b) Multiple mutations.
-
0%
c) Polygenic mutation.
-
0%
d) Monogenic mutation.
Q.46.
on Q352) Which of the following is not related with sex chromosome X or Y?
-
0%
a) Turner’s syndrome.
-
0%
b) Klinefelter’s syndrome.
-
0%
c) Down’s syndrome.
-
0%
d) Haemophilia and colour blindness.
Q.47.
on Q406) Which of the following is the unit of inheritance ?
-
0%
a) Phenotype
-
0%
b) Genotype
-
0%
c) Gene
-
0%
d) Genome
Q.48.
on Q353) When a tall plant with round seeds (TTRR) crossed with a dwarf plant with wrinkle seeds (ttrr). The F1 generation consists of tall plants with round seeds. What would be the proportion of dwarf plant with wrinkle seeds in F1 generation?
-
0%
a) 0.
-
0%
b) 1/2
-
0%
c) 1/4
-
0%
d) 1/16
Q.49.
on Q354) Heterozygous tall plants were crossed with dwarf plants what will be the ratio of dwarf plants in the following progency ?
-
0%
a) 50%
-
0%
b) 25 %
-
0%
c) 75%
-
0%
d) 100%
Q.50.
on Q355) 1: 1: 1: 1 ratio shows
-
0%
a) Monohybrid cross
-
0%
b) Dihybrid cross
-
0%
c) Back cross
-
0%
d) Dihybrid test cross