Q.1.
on Q512) Recessive allele of an enzyme coding gene may be responsible for the production of
-
35%
a) The normal/less efficient enzyme
-
47%
b) A non-functional enzyme
-
6%
c) No enzyme at all
-
12%
d) Any of the above.
Q.2.
on Q513) Two heterozygous tall plants are intercrossed, what percentage of tall progeny will be homozygous tall?
-
38%
a) 25
-
15%
b) 33
-
38%
c) 50
-
8%
d) 66
Q.3.
on Q514) As, 5 progenies are not showing large enough data to conclude that grey parent has no g allele to contribute for white progeny. Hence the genotype can be GG or gg. Grey was crossed with white, 5 grey and 0 white were formed. The genotype of the grey parent will be
-
0%
a) Gg
-
0%
b) GG
-
80%
c) Both a and b
-
20%
d) Gg
Q.4.
on Q515) If Ram has a brother Shyam suffering from Cystic Fibrosis, what is the probability of Ram being a carrier as his parents are normal?
-
40%
a) 1/4
-
50%
b) 1/2
-
10%
c) 2/3
-
0%
d) 3/4
Q.5.
on Q516) The mutation happened in DNA which can alter the reading frame of m – RNA is:
-
0%
a) Transition.
-
18%
b) Transversion.
-
27%
c) Point mutation.
-
55%
d) Frame – shift mutation.
Q.6.
on Q517) If a character is controlled by a multiple allelic gene with six alleles. What will be the probable genotypes of respective genes in the population?
-
33%
a) 42
-
44%
b) 21
-
22%
c) 16
-
0%
d) 9
Q.7.
on Q518) This is reversal of mutation
-
22%
a) Spontneous mutation
-
0%
b) Zygotic mutation
-
33%
c) Back mutation
-
44%
d) Recessive mutation
Q.8.
on Q519) Sickle cell anaemic person will have
-
41%
a) Abnormal beta globin chain and sickle shaped RBC
-
14%
b) Normal beta globin chain and sickle shaped RBC
-
32%
c) Abnormal beta globin chain and biconcave RBC
-
14%
d) Normal beta globin chain and biconcave RBC
Q.9.
on Q520) In sickle cell anaemia, point mutation causes the change of codon from:
-
8%
a) CTC to CAC.
-
58%
b) GAG to GUG.
-
25%
c) Glutamic acid to valine.
-
8%
d) Valine to glutamic acid.
Q.10.
on Q521) In ABO blood grouping how many genotypes show co-dominance?
-
11%
a) 1
-
22%
b) 2
-
33%
c) 3
-
33%
d) 4
Q.11.
on Q522) Number of different types of gametes produced by genotype AABBCCDDEEFFGGHH will be
-
22%
a) 20
-
0%
b) 2
-
33%
c) 102
-
44%
d) zero
Q.12.
on Q523) The maximum different types of progenies formed by the mating between
-
14%
a) 4
-
29%
b) 8
-
57%
c) 16
-
0%
d) 2
Q.13.
on Q524) The sex determining gene, SRY gene in humans produce:
-
43%
a) Testosterone.
-
29%
b) TDF (Testis determining factor).
-
14%
c) SXL (Sex X lethal).
-
14%
d) ABP (Androgen binding proteins).
Q.14.
on Q525) Which one of the following individuals can produce 16 different gametes?
-
0%
a) AaBbccDd.
-
60%
b) AaBbccDDEeFf.
-
20%
c) AaBbCcddEEFF.
-
20%
d) AaBbCcDDEeFf.
Q.15.
on Q526) A useful process for determining whether an individual is homozygous or heterozygous is
-
14%
a) cross - breeding
-
0%
b) self fertilization
-
29%
c) Back - crossing
-
57%
d) Test cross
Q.16.
on Q527) What was the expected ratio of F2 by Bateson and Punnet in their dihybridization experiment done on Lathyruas odoratus?
-
83%
a) 9 : 3 : 3 : 1
-
0%
b) 11 : 1 : 1 : 3
-
17%
c) 12 : 1 : 1 : 3
-
0%
d) 9 : 3 : 2 : 2
Q.17.
on Q528) Out of the marked portions X, Y and Z, in which region the male worm develop ?
-
0%
a) X
-
17%
b) Y
-
17%
c) Z
-
67%
d) All the three regions
Q.18.
on Q529) Down's Syndrome is caused by an extra copy of chromosome numberWhat percent age of off spring produced by an affected mother and a normal father?
-
20%
a) 100%
-
20%
b) 75%
-
60%
c) 50%
-
0%
d) 25%
Q.19.
on Q530) In a dihybrid cross between AABB and aabb the ratio of AABB, AABb, aaBb, aabb in F2 generation is ... ....
-
50%
a) 9 : 3 : 3: 1
-
33%
b) 1: 1: 1: 1
-
17%
c) 1: 2: 2: 1
-
0%
d) 1 : 1 : 2 : 2
Q.20.
on Q531) In human child, sex is determined by
-
0%
a) Size and number of sperms in semen
-
0%
b) Size of egg to be fertilized
-
60%
c) Sex chromosomes of father
-
40%
d) Sex chromosomes of mother
Q.21.
on Q532) If a colour-blind woman marries a normal visioned man, their sons will be:
-
50%
a) all normal visioned
-
33%
b) one-half colour-blind and one-half normal
-
0%
c) three-fourths colour-blind and one-fourth normal
-
17%
d) all colour-blind
Q.22.
on Q533) In the results, F2 generation of Mendelian dihybrid cross in pea plant. The ratio of yellow and wrinkled seeded pea plant is
-
0%
a) 1/16
-
17%
b) 3/16
-
83%
c) 4/16
-
0%
d) 7/16
Q.23.
on Q534) If the offspring is aa, what possible combination of parental genotype would have produced these progenies?
-
0%
a) AA and aa
-
0%
b) Aa and AA
-
40%
c) aa and AA
-
60%
d) Aa and Aa
Q.24.
on Q535) All mutations in genetic material may not lead to change in amino acid composition. Though there is a change in the codon, it is not expressed in the amino acids. Such mutations are called as silent mutations'. Which of the following alteration of codons ATTGCC is not a silent mutation?
-
17%
a) ATCGCC.
-
17%
b) ATTGCA.
-
33%
c) ATTTGC.
-
33%
d) ATCGCG.
Q.25.
on Q536) Diseases that are caused by the malfunction of a pleiotropic gene are:
-
17%
a) cured by dietary restrictions
-
33%
b) reversible by gene therapy
-
17%
c) called as syndromes
-
33%
d) extremely rare
Q.26.
on Q537) How many pairs of contrasting traits studied by Mendel were related to pod?
-
0%
a) 1
-
43%
b) 2
-
0%
c) 3
-
57%
d) 4
Q.27.
on Q538) Types of gametes produced by a homozygous parent
-
20%
a) many
-
40%
b) single type
-
20%
c) depends upon number of genes
-
20%
d) depends upon number of chromosomes
Q.28.
on Q539) What is wrong with respect to sex determination in honey bee?
-
33%
a) Unfertilized egg develops as a male by means of parthenogenesis.
-
0%
b) Union of sperm and egg develops as a female
-
50%
c) All workers and males will have 16 chromosomes while queen will have 32 chromosomes.
-
17%
d) Males produce sperms by mitosis.
Q.29.
on Q540) In Drosophila, the sex is determined by:
-
0%
a) The ratio of pair of X – chromosomes to the pairs of autosomes.
-
83%
b) X and Y chromosomes.
-
17%
c) The ratio of number of X – chromosomes to the number of autosomes.
-
0%
d) Whether the egg is fertilized or developed parthenogenetically.
Q.30.
on Q541) The reason for the resemblance of F1 with any one of the parent is explained in the following law:
-
60%
a) Law of dominance.
-
20%
b) Law of segregation.
-
20%
c) Law of independent assortment.
-
0%
d) Chromosomal theory of inheritance.
Q.31.
on Q542) Which of the following is not a X-linked recessive disease?
-
17%
a) Haemophilia
-
17%
b) Colour blindness
-
33%
c) β Thalassemia
-
33%
d) Glucose-6-phosphatte dehydrogenase deficiency.
Q.32.
on Q543) Male heterogametey is not seen in:
-
40%
a) Humans
-
0%
b) Melandrium album
-
40%
c) Birds
-
20%
d) Fruit fly
Q.33.
on Q544) A man whose father was colour-blind marries a woman, who has a colour-blind mother and normal father. What percentage of male children of this couple will be colour-blind?
-
17%
a) 25%
-
50%
b) 0%
-
17%
c) 50%
-
17%
d) 75%
Q.34.
on Q545) In which of the following one may observe variation in DNA?
-
25%
a) Fragmentation
-
0%
b) Budding
-
25%
c) Amitosis
-
50%
d) mutation
Q.35.
on Q546) Which among the following abnormal gamete can cause the formation of Turner’s syndrome?
-
40%
a) 23A + X egg.
-
40%
b) 21A + X sperm.
-
0%
c) 22A + No allosome egg.
-
20%
d) 22A + XX egg.
Q.36.
on Q547) Tay-Sachs disease results due to lack of enzyme
-
20%
a) glucokinase
-
0%
b) hexosaminidase A
-
80%
c) Pyruvate kinase
-
0%
d) Na+ — K+ ATPase
Q.37.
on Q548) Which Mendelian idea is depicted by a cross in which the F1 generation resembles both the parents?
-
20%
a) Incomplete dominance
-
60%
b) Law of dominance
-
0%
c) Inheritance of one gene
-
20%
d) Co dominance
Q.38.
on Q549) Boy born to a physically normal couple has been diagnosed with a genetic disorder, this could be
-
20%
a) Y- linked trait.
-
20%
b) Autosomal dominant trait
-
0%
c) X- linked dominant trait
-
60%
d) X- linked recessive trait
Q.39.
on Q550) Identify the wrongly matched pair:
-
0%
a) W. Bateson – Allele, homozygous.
-
60%
b) Johansen – Gene.
-
20%
c) Hugo de Vries – Holland.
-
20%
d) Eric Von Tschenmark – America.
Q.40.
on Q551) The chromosome movement during meiosis have been worked out
-
40%
a) 1900
-
40%
b) 1902
-
0%
c) 1911
-
20%
d) 1930
Q.41.
on Q552) A human male produces sperms with the genotypes AB, Ab, aB and ab pertaining to two biallelic characters in equal proportions. What is the corresponding genotype of this person?
-
25%
a) AaBb
-
50%
b) AaBB
-
0%
c) AABb
-
25%
d) AABB
Q.42.
on Q553) If dihybrid mulatto male (AaBb) is crossed with white female, then the ratio of mulatto and white offspring will be-
-
20%
a) 1:6
-
40%
b) 1:1
-
40%
c) 4:1
-
0%
d) 2:1
Q.43.
on Q554) The insertion or deletion of a base pair into the genetic code will cause a frame shift mutation unless the number of base pairs inserted or deleted is:
-
40%
a) One
-
40%
b) Two
-
20%
c) three
-
0%
d) Ten
Q.44.
on Q555) A cross between tall pea plant and its recessive parent is known as
-
0%
a) Back cross
-
75%
b) Test cross
-
25%
c) Recessive cross
-
0%
d) Dominant cross