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Inheritance And Variation Mcq
Quiz 5
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Q.1
Monohybrid crossing involves ... .. [ CPMT 1993 ]
0%
a) Individuals of two different parents
0%
b) Individuals different in one trait
0%
c) Individuals different in two traits
0%
d) Individuals with parent
Explanation
A monohybrid cross is a cross between two organisms with different variations at one genetic locus of interest. A cross between two types of plants of same species considering only the transmission of one character is called monohybrid cross. For example, a cross between tall pea plants and dwarf pea plant that is considering only the height of the parents is a monohybrid cross. Answer : (b)
Q.2
Universal donor blood group is ... .. [ JKCMEE 2005 ]
0%
a) AB
0%
b) O
0%
c) A
0%
d) B
Explanation
Blood group O do not carry any antigen in the coating of their erythrocytes and makes Anti-A and Anti-B antibodies. This makes O an universal blood group. Answer : (b)
Q.3
Two genetic loci produce identical phenotypes in cis as will as trans position. They are ... ... [ CBSE 1995 ]
0%
a) Pseudoalleles
0%
b) Multiple alleles
0%
c) Different genes
0%
d) Parts of same gene
Explanation
Two genes are said to be in cis position if the dominant alleles of both genes are on the same chromatid of a pair of homologous chromosomes. Two genes are in trans position if the dominant alleles of both genes are on different chromatids of a pair of homologous chromosomes. Pseudoallelism is a state in which two closely linked genes produce identical phenotypes whether the genetic loci are in cis or trans position. Answer : (a)
Q.4
Which one of the following can not be explained on the basis of Mendel's law of Dominance ... .. [ CBSE 2010 ]
0%
a) Out of one pair of factors, one is dominant and the other recessive.
0%
b) Alleles do not show any blending and both the characters recover as such in F2 generation
0%
c) Factors occur in pairs
0%
d) Discrete unit controlling a particular character is called a factor
Explanation
Allele do not show any blending and both the character recover as such in F2 generation. This characteristics is expressed by Mendel’s law of segregation. Answer : (b)
Q.5
Hybrid of pure red flowered and white flowered Pea is crossed to pure red flower plant. The progeny shall be ... ... [ RPMT 2002 ]
0%
a) White flowered
0%
b) Red flowered
0%
c) Both red and white flowered plants
0%
d) Mostly red flowered pants
Explanation
Gametes
R
r
R
RR (red flower)
Rr ( red flower))
R
RR (red flower)
Rr (red flower)
Hybrid of pure red flower and pure white flower will heterozygous red flower (Rr). When heterozygous red flower (Rr) is crossed with pure red flower (RR), all the progeny will have dominant character i.e., red flower. Rr × RR Progeny Answer : (b)
Q.6
on Q405) The longer the chromosome of an organism, the more genetic variability it gets from,
0%
a) Independent assortment
0%
b) Linkage
0%
c) Crossing over
0%
d) Mutation.
Explanation
Answer:(c)
Q.7
Incomplete dominance ratio of red, pink and white in Four O'clock is ... .. [ AMU 2010 ]
0%
a) 1:2:1
0%
b) 1:1:2
0%
c) 1:2:2
0%
d) 2:2:1
Explanation
Gametes
R
r
R
RR (red flower)
Rr (pink flower)
r
Rr(pink flower)
rr (white flower)
Rr × Rr Red: pink: white = 1: 2 : 1 Answer : (a)
Q.8
When both alleles express their effect on being present together, the phenomenon is called ... .. [ DPMT 2008 ]
0%
a) Dominance
0%
b) Codominance
0%
c) Pseudodominance
0%
d) Amphidominance
Explanation
Codominance: It is the phenomenon of two alleles lacking dominant=recessive relationship and both expressing themselves in the organism. Answer : (b)
Q.9
What is true of law of independent assortment ? ... .. [ Manipal 200 7]
0%
a) Applicable to all the dominant alleles
0%
b) Applicable to all genes present on the same chromosome
0%
c) Not applicable to genes present on the same chromosome
0%
d) Applicable to all recessive alleles
Explanation
The law of independent assortment is applicable to only those factors or genes which are present on different chromosomes. The law applies only to gene pairs on different pairs of homologous. When a cross is made between two individuals different from each other in two or more characters, then the inheritance of one character is independent of the inheritance of another character. It is called Law of independent assortment. This is correct if the genes are present on two different chromosomes. But if the genes are present on the same chromosomes, they may or may not show independent assortment, i.e. Linkage. Answer : (c)
Q.10
Incomplete dominance is found in ... ... [ MPPMT 2010 ]
0%
a) Neurospora crassa
0%
b) Lathyrus odoratus
0%
c) Pisum sativum
0%
d) Antirrhinum / Mirabilis
Explanation
Incomplete dominance is seen in Mirabilis jalapa (four o’clock) and Antirrhinum majus (snap dragon or dog flower). Answer : (d)
Q.11
Mating of an organism to double recessive for determining homozygosity over heterozygosity is .. .... [ AIIMS 2006 ]
0%
a) Reciprocal cross
0%
b) Back cross
0%
c) Dihybrid cross
0%
d) Test cross
Explanation
Crossing of F1 individual having dominant phenotype with its homozygous recessive parents is called test cross. The test cross is used to determine whether the individuals exhibiting dominant characters are homozygous or heterozygous. Answer : (d)
Q.12
A tall plant with round seeds (TTRR) crossed with a dwarf wrinkle seeded plant (ttrr). F1 has tall plants with rounded seeds. What is the proportion of dwarf plants with wrinkled seeds in F2 generation... .. [ KCET 2007 ]
0%
a) Zero
0%
b) 1/2
0%
c) 1/4
0%
d) 1/16
Explanation
Gametes
TR
Tr
tR
tr
TR
TTRR (tall, round seed)
TTRr (tall,round seed)
TtRR (tall,round seed)
TtRr (tall, round seed)
Tr
TTRr (tall, round seed)
TTrr ( tall, wrinkled seed)
TtRr (tall,round seed)
Ttrr (tall, wrinkled seed)
tR
TtRR (tall, round seed)
TtRr (tall,round seed)
ttRR (dwarf, round seed)
ttRr (dwarf, round seed)
tr
TtRr (tall, round seed)
Ttrr (tall, wrinkled seed)
ttRr (dwarf, round seed)
Ttrr (dwarf, wrinkled seed)
Dwarf plant with wrinkled seed = 1/16 Answer : (d)
Q.13
In quantitative inheritance F2 ratio obtained in a dihybrid cross is ... .. [ DPMT 2002 ]
0%
a) 1:4:6:4:1
0%
b) 15:1
0%
c) 12:3:1
0%
d) 9:7
Explanation
Quantitative inheritance: It is a type of inheritance controlled by more genes in which the dominant alleles have cumulative effect with each dominant allele expressing a part or unit of trait, the full trait being shown only when all the dominant alleles are present. The genes involved are called polygenes. Quantitative inheritance is therefore, also called polygenic inheritance. Polygenic inheritance does not follow Mendelian ratio. Ratio of F2 generation is 1 : 4 : 6 : 4 : 1. Answer : (a)
Q.14
Monohybrid ratio is .... [ Bih. PMT 1994 ]
0%
a) 3:1
0%
b) 9:7
0%
c) 1:2
0%
d) 9:3:3:1
Explanation
No. of traits (n)
Experiment
Types of gametes (2
n
)
No. of offsprings (gametes)
2
No. of phenotype (2
n
)
No. of genotype (3
n
)
Phenotypic ratio
Genotypic ratio
1
Monohybrid cross
2
4
2
3
3:1
1:2:1
Answer : (a)
Q.15
Test cross is a cross between ... .. [ DPMT 2008 ]
0%
a) Hybrid × Dominant parent ( Tt × TT)
0%
b) Hybrid × recessive parent ( Tt × tt )
0%
c) Hybrid × Hybrid ( Tt × Tt)
0%
d) All the above
Explanation
Crossing of F1 individual having dominant phenotype with its homozygous recessive parents is called test cross. The test cross is used to determine whether the individuals exhibiting dominant characters are homozygous or heterozygous. Answer : (b)
Q.16
A cross between tall and dwarf Pea plants, yielded 124 tall and 126 dwarf plants. gneotype of parents would be ... ... [ WB 2012]
0%
a) TT × TT
0%
b) TT × Tt
0%
c) Tt × Tt
0%
d) Tt × tt
Explanation
Ratio of Tall : dwarf is almost 1 : 1. It is possible when one parent is heterozygous tall plant (Tt) and recessive dwarf plant (tt) Answer : (d)
Q.17
Ratio 9:7 is due to ... ... [ AMU 1993 ]
0%
a) Supplementary genes
0%
b) Lethal genes
0%
c) Complementary genes
0%
d) Epistatic genes
Explanation
Characters
Expected ratios
Example
Monohybrid cross
Phenotypic = 3 : 1
Genotypic = 1 :2 : 1
Pisum sativum
Dihybrid cross
Phenotypic = 9:3:3:1
Pisum sativum
Incomplete dominance
1 : 2 : 1
Mirabilis jalapa
Complementary genes
9 : 7
Lathyrus odoratus
Supplementary genes
9 : 3 : 4
Coat colour of mice
Collaborative supplementary genes
9 : 3 : 3 : 1
Poultry birds – comb pattern
Dominant epistasis
12 : 3 : 1
Fruit colour in
Curcurbita
Recessive epistasis
9 : 3 : 4
Coat colour in mice/pigmentation in onion bulb
Duplicate genes
15 : 1
Fruit shape in
Capsella bursapastoris
Polymeric gene
9 : 6 : 1
Cucurbita pepo
Suppresor gene
13:3
Leaf colour of rice
Answer : (c)
Q.18
Height in humans is ... .. [CPMT 2005 ]
0%
a) Somatogenic variation
0%
b) Discontinuous variation
0%
c) Continuous variation
0%
d) Both B and C
Explanation
Continuous variation is the variation that has no limit on the value that can occur within a population . Examples of continuous variation include things like a person's height and weight. Answer : (c)
Q.19
Donors and recipients of blood transfusion can be ... .. [ MPPMT 1995 ]
0%
a) Only father and son
0%
b) Only brother and sister
0%
c) Only maternal uncle and niece
0%
d) All the above
Explanation
Answer : (d)
Q.20
Crossing over in diploid organism is responsible for ... .. [ CBSE 1998 ]
0%
a) Dominance of genes
0%
b) Linkage between genes
0%
c) Recombination of linked genes
0%
d) Segregation of alleles
Explanation
Crossing over is an exchange of genes/chromosomal parts to break established linkages and formation of new linkages. It brings new combinations of genes (recombinations) which are different from parents thus introducing variations. Answer : (c)
Q.21
An organism with two identical alleles is .... [ CBSE 1992 ]
0%
a) Dominant
0%
b) Hybrid
0%
c) Heteroxygous
0%
d) Homoxygous
Explanation
The diploid condition in which the alleles at a given locus are identical is called homozygous or pure. In homozygous condition, organism have two similar genes or alleles for a particular character in homologous pair of chromosomes. Answer : (d)
Q.22
on Q481) Identify the missing amino acids correctly in the β chain of haemoglobin (HbA peptide):
0%
a) Histidine, proline, glutamic acid.
0%
b) Histidine, glutamic acid, valine.
0%
c) Proline, glutamic acid, Histidine.
0%
d) Histidine, proline, valine.
Explanation
Answer:(a)
Q.23
Epistasis in which dihybrid ratio of 9 : 3: 3:1 between Aa Bb × AaBb is modified is ... .. [ AIIMS 1997 ]
0%
a) Dominance of one allele on another allele at the same locus
0%
b) Dominance of one allele on another allele at both its loci
0%
c) Interaction of two alleles at different locus
0%
d) Interaction between two alleles at same locus
Explanation
Epistasis is the interaction between genes present at two separate loci in which one gene suppresses or masks the expression of other gene. The gene that masks the effect of other gene is nown as inhibiting or epistasis factor and the one which is being prevented from exhibiting itself is known as hypostatic factor. Epistasis works at intergenic level. Answer : (b)
Q.24
Sickle cell anaemia is caused by substitution of sixth position ... ... [ Kerala 2012 ]
0%
a) Valine by glutamic acid in α-chain of Hb
0%
b) Valine by glutamic acid in β-chain of Hb
0%
c) Glutamic acid by valine in α-chain of Hb
0%
d) Glutamic acid by valine in β-chain of Hb
Explanation
Sickle cell anemia is caused by the substitution of Glutamic acid (Glu) by Valine (Val) at the sixth position of the beta globin chain of the haemoglobin molecule. The substitution of amino acid in the globin protein results due to the single base substitution at the sixth codon of the beta globin gene from GAG to GUG. The mutant haemoglobin molecule undergoes polymerisation under low oxygen tension causing the change in the shape of the RBC from biconcave disc to elongated sickle like structure. Answer : (d)
Q.25
In a case of incomplete dominance, true breeding red flowers plant (RR) is crossed with true breeding white flowered plant (rr). What would be correct F2 ratio? ... ... [AMU 2009]
0%
a) 1 red:2pink:1white
0%
b) 3 red:1 white
0%
c) 1 red : 1 pink : 2 white
0%
d) 2 red :1 pink : 1 white
Explanation
Gametes
R
r
R
RR (red flower)
Rr (pink flower)
r
Rr (pink flower)
rr (white flower)
Red flower (RR) × white flower (rr) → Pink flower (Rr) Pink flower (Rr) is self-crossed. Red : pink : white = 1 : 2 : 1 Answer : (a)
Q.26
A cross between two heterozygous individuals will yield homozygous individuals ... .. [ Odisha 2012 ]
0%
a) 2
0%
b) 4
0%
c) 6
0%
d) 8
Explanation
Gametes
T
t
T
TT (homozygous)
Tt (heterozygous)
t
Tt (heterozygous)
Tt (heterozygous)
Two heterozygous individual when crossed give 2 homozygous individual and 2 heterozygous individual. Example: Tt × Tt Answer : (a)
Q.27
Epistasis is due to ... .. [ JIPMER 2000 ]
0%
a) Interaction of two alleles of the same gene
0%
b) interaction of two separate genes
0%
c) polygenes
0%
d) Multiple alleles
Explanation
Epistasis is the interaction between genes present at two separate loci in which one gene suppresses or masks the expression of other gene. The gene that masks the effect of other gene is nown as inhibiting or epistasis factor and the one which is being prevented from exhibiting itself is known as hypostatic factor. Epistasis works at intergenic level. Answer : (b)
Q.28
A pure tall Pea plant is crossed with pure dwarf Pea plant. the progeny is self-pollinated. the ratio of true breeding tall Pea plants to true breeding dwarf Pea plants shall be ... .... [ MPPMT 2007 ]
0%
a) 2 : 1
0%
b) 1 : 1
0%
c) 3 : 1
0%
d) 1 : 2
Explanation
Pure tall pea plant (TT) is crossed with dwarf pea plant (tt). The progeny produced is tall pea plant having genotype of Tt. These progeny is self-crossed Tt × Tt = TT (pure tall ) : Tt (heterozygous tall) : tt (pure dwarf) = 1 : 2 : 1 Pure tall : pure dwarf = 1 : 1 Answer : (b)
Q.29
Blood group of a couple are AB and O. the possible blood group of children would be ... ... [ Manipal 2004 ]
0%
a) O group only
0%
b) AB blood group
0%
c) A or B
0%
d) AB and O
Explanation
I
A
I
B
I
O
I
A
I
O
(A blood group)
I
B
I
O
(B blood group)
I
O
I
A
I
O
(A blood group)
I
B
I
O
(B blood group)
Answer : (c)
Q.30
Alleles represent ..... [ JIPMER 2003 ]
0%
a) Different forms of gene
0%
b) Same loci on homologous chromosomes
0%
c) Two or more forms
0%
d) All the above
Explanation
An allele is a variant form of a gene. Some genes have a variety of different forms, which are located at the same position, or genetic locus, on a chromosome Answer : (d)
Q.31
The offspring of mating between two pure breeding strains are called ... ...[ Odisha 2007 ]
0%
a) hybrid
0%
b) progeny
0%
c) cybrid
0%
d) heterosis
Explanation
A hybrid is the offspring resulting from combining the qualities of two organisms of different breeds, varieties, species or genera through sexual reproduction. Answer : (a)
Q.32
Ratio 9:3:3:1 is due to ... ... [ AMU 1993 ]
0%
a) Duplicate genes
0%
b) Lethal genes
0%
c) Monohybrid cross
0%
d) Dihybrid cross
Explanation
No. of traits (n)
Experiment
Types of gametes (2
n
)
No. of offsprings (gametes)
2
No. of phenotype (2
n
)
No. of genotype (3
n
)
Phenotypic ratio
Genotypic ratio
2
Dihybrid cross
4
16
4
9
9:3:3:1
2:4:2:1:2:1:1:2:1
Answer : (d)
Q.33
White eye is a sex linked recessive trait in Drosophila. In cross of white eyed female with normal male, what are phenotypes of F1 generation ... ..
0%
a) All normal
0%
b) All males white eyed, all females normal
0%
c) 50% females and all males white eye
0%
d) 50% males and 50% females white eyed
Explanation
Gametes
XW
XW
X
XWX (normal female)
XWX (normal female)
Y
XWY (white eye male)
XWY (white eye male)
Female Drosophila with white eye is crossed with normal male. Since white eye is a sex linked recessive trait, it is expressed when in case of XWXW or XWY. XWXW × XY Answer : (b)
Q.34
Branch of biology dealing with heredity and variations is ... ... [ MPPMT 1998 ]
0%
a) Ecology
0%
b) Evolution
0%
c) Palaeontology
0%
d) Genetics
Explanation
Genetics is the branch of biological sciences which deals with transmission of characteristics from one generation to next and also the action of hereditary units called genes as they bring about the characteristics which they control. Modern genetics is concerned with the study of genes, the units of heredity that controls the characteristics of organism. Answer : (d)
Q.35
In Mendel's experiments with Garden Pea, round seed shape (RR) was dominant over wrinkled seed (rr), yellow cotyledons (YY) was dominant over green cotyledons (yy). What are expected phenotypes in F2 generation RR × rryy ? ... .. [ CBSE 2006 ]
0%
a) Only wrinkled seeds with green cotyledons
0%
b) Only wrinkled seeds with yellow cotyledons
0%
c) Only round seeds with green cotyledons
0%
d) Round seeds with yellow cotyledons and wrinkled seeds with green cotyledons
Explanation
Gametes
RY
Ry
rY
ry
RY
RRYY (round, yellow)
RRYy (round,yellow)
RrYY (round, yellow)
RrYy (round, yellow)
Ry
RRYy (round, yellow)
RRyy (round, green)
RrYy (round, yellow)
Rryy (round, green)
rY
RrYY (round, yellow)
RrYy (round, yellow)
rrYY ( wrinkled, yellow)
rrYy (wrinkled, yellow)
ry
RrYy (round, yellow)
Rryy ( round, green)
rrYy ( wrinkled, yellow)
Rryy (wrinkled, green)
RRYY × rryy → F1 generation RrYy Answer : (d)
Q.36
Trihybrid ratio is ......
0%
a) 27:9:9:9:3:3:3:1
0%
b) 27:9:9:6:6:3:3:1
0%
c) 1:6:15:20:15:6:1
0%
d) 36:6:6:6:3:3:3:1
Explanation
No. of traits (n)
Experiment
Types of gametes (2
n
)
No. of offsprings (gametes)
2
No. of phenotype (2
n
)
No. of genotype (3
n
)
Phenotypic ratio
Genotypic ratio
3
Trihybrid cross
8
64
8
27
(3:1)
3
(1:2:1)
3
(3 : 1)3 = 27 : 9 : 9 : 9 : 3 : 3: 3 : 1 Answer : (a)
Q.37
on Q482) What is the phenotypic and genotypic ratio of F2 generation in incomplete dominance?
0%
a) 3:1 and 1:2:1
0%
b) 1:2:1 and 3:1
0%
c) 1:2:1
0%
d) 1:1:1
Explanation
Genotypic ratio and phenotypic ratio is same in incomplete dominance. The ratio is 1 : 2 : 1. Answer:(c)
Q.38
In Red-White flowered cross of Mirabilia jalapa, F2 generation has red, pink and white flowered plants in the ratio of ... ... [ AIIMS 1994 ]
0%
a) 1:2:1
0%
b) 1:0:1
0%
c) 2:1:1
0%
d) 1:1:2
Explanation
Gametes
R
r
R
RR (red flower)
Rr (pink flower)
r
Rr (pink flower)
rr (white flower)
Red flower (RR) × white flower (rr) → Pink flower (Rr) Pink flower (Rr) is self-crossed. Red : pink : white = 1 : 2 : 1 Answer : (a)
Q.39
Pleiotropic gene has ... ... [ AMU 1991 ]
0%
a) Multiple genotype
0%
b) Single genotype
0%
c) Single phenotype
0%
d) Multiple phenotype
Explanation
The ability of a gene to have multiple phenotypic effect because it influences a number of characters simultaneously is known as pleiotropy. The gene having a multiple phenotypic effect because of its ability to control expression of a number of characters is called pleiotropic gene. Answer : (d)
Q.40
Yellow colour is dominant over green colour. in a generation of 50% yellow and 50% green individuals, the parents are ... ... [ MPPMT 1994 ]
0%
a) Both homozygous
0%
b) Both heterozygous
0%
c) One of them is heterozygous
0%
d) None of the above
Explanation
Gametes
Y
y
y
Yy (yellow)
Yy (green)
y
Yy (yellow)
Yy (green)
Yy × yy → Progeny Answer : (c)
Q.41
G.J. Mendel died in ... .. [ AMU 1997 ]
0%
a) 1984
0%
b) 1894
0%
c) 1884
0%
d) 192
Explanation
Gregor Johann Mendel was born on 1822 and died in year 1884 Answer : (c)
Q.42
In Pea, wrinkling of seeds is due to non-formation of starch because of the absence of enzyme... .. [ CBSE 2001 ]
0%
a) Amylase
0%
b) invertase
0%
c) Branching enzyme
0%
d) Diastase
Explanation
In pea, the gene which controls starch synthesis also controls the shape of the seed. In the pea plant with wrinkled seeds, this gene is not involved in the synthesis of starch due to the absence of enzyme starch synthase. It is a branched enzyme. Answer : (c)
Q.43
Back cross is ... ... [ Kerala 2000 ]
0%
a) F1 × F1
0%
b) F1 × Recessive parent
0%
c) F1 × Dominant parent
0%
d) F1 × Any parent
Explanation
Backcross is a cross of F1 hybrid with either of two parents Answer : (d)
Q.44
Alleles are ..... ..[ EAMCET 1999 ]
0%
a) Genes found on autosomes
0%
b) Pair of genes governing a specific character like height
0%
c) Genes governing eye characters
0%
d) None of the above
Explanation
A pair of contrasting is called allele. They are alternative form of same gene. Example T and t for height. One set of allele govern one specific character. Answer : (b)
Q.45
Hybrids are generally superior to parents due to ... .. [ DPMT 2003 ]
0%
a) Heterosis
0%
b) Homozygosity
0%
c) Heterozygosity
0%
d) Parents are generally weak
Explanation
Hybrid vigour or heterosis is the superiority of hybrid over either of its parents in one or more traits. Answer : (a)
Q.46
A test cross is performed to know ... ... [ CBSE 2012]
0%
a) Genotype of F2 dominants
0%
b) Linkage between two traits
0%
c) Number of alleles of a gene
0%
d) Success of intervarietal and interspecific cross
Explanation
Crossing of F1 individual having dominant phenotype with its homozygous recessive parents is called test cross. The test cross is used to determine whether the individuals exhibiting dominant characters are homozygous or heterozygous. Answer : (a)
Q.47
A blue fowl obtained from mating between black and white fowls, is self-crossed. The F2 ratio is ... .. [ AIIMS 1997 ]
0%
a) 1 black : 2 white : 1 blue
0%
b) 2 black : 1 white : 1 blue
0%
c) 1 black : 2 blue : 1 white
0%
d) None of above
Explanation
This is an example of incomplete dominance. F2 phenotypic ratio is same as genotypic ratio i.e., 1 : 2 : 1 1 black : 2 blue : 1 white Answer : (c)
Q.48
Human skin colour is polygenic trait with each dominant determining a part of melanin deposition while the recessive are coding for no melanin. if a very dark skinned person marries a very light skinned women, the chances of a very dark skinned offspring are ..... [ kerala 2006 ]
0%
a) 0
0%
b) 1/4
0%
c) 5/8
0%
d) 3/64
Explanation
Human colour is controlled by three pair of genes. The progeny of the parents with genotype AABBCC and aabbcc will have intermediate color in the F1 generation, i.e. genotype would be AaBbCc. Further, in the F2 generation of two triple heterozygotes parents — AaBbCc x AaBbCc — will produce varying skin colors ranging from very dark to very light, the ratio of which would range in 1:6:15:20:15:6:1. Out of 64 progeny, only one will have very dark skin. Answer : (a)
Q.49
The gene for right handedness is dominant over the gene for left handedness. Most probable gene types of two right handed parents with left handed child is ... .. [Odisha 2006 ]
0%
a) RR × rr
0%
b) rr × Rr
0%
c) RR × Rr
0%
d) Rr × Rr
Explanation
Right handed gene is dominant over left handed gene. The child is expressing recessive trait. This is possible when both the parents have heterozygous genotype expressing dominant trait. So genotype of the parents are Rr. Answer : (d)
Q.50
Mendel enunciated principles of inheritance .... .. [ MPPMT1995]
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a) Two
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b) Three
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c) Four
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d) Five
Explanation
Mendel enunciated prinicples of inheritance. They are (1) Law of dominance (2) Law of segregation (3) Law of independent assortment. Answer : (b)
0 h : 0 m : 1 s
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