HClO2 and BF3 have sp2 hybridization, but due to symmetric arrangement of F around B net dipole moment is zero Answer: (a)

there is intermolecular hydrogen bonding in p-nitrophenol while in o-nitrophenol there is intra hydrogen bonding Answer: (c)

Answer:(c)

Answer: (a)

Answer: (b)

The structure of PO43- is Here three unit negative charge is shared by four oxygen atoms ∴ formal charge=-3/4 = 0.75 Five bon pairs are shared between four P-P bond ∴ B.O of P -O=5/4=1.25Answer: (c)

According to Fajan's rules of polarization, more the size of anion, more easily it will be polarized and hence, the compound will be more covalent. Less the size of cation, more will be ita polarizing power and hence compound will be more covalent. Answer:(a)

For group VA element elctronegativity decreases from N to Bp All the options have same structure but electro negativity is highest for N Answer: (d)

Answer: (b)

Answer: (a)

CO2 is sp hybridized, hence linear, while HgCl2 is also linear molecule hence isostructural Answer:(a)

PF5 have 40 valence electron Now 40 ÷ 8=5(Q) + 0(R) , thus hybridization is sp3d hence trigonal bipyramidalAnswer: (c)

Nitrogen can form NCl3, N2O5, Ca3N2 Nitrogen due to absence of empty d-orbitals canot extend its covalency by more than 3 and hence do not form NCl5 Due to its sma;; size and high electronegativity it can accept 3 e- to form N3-3N2) In above question covalency of x in xCl3 is 3 option'c' is correct as Nitrogen do not have d orbital to form XCl5Answer: (c)

Answer: (c)

Metallic Bond: The force of attaction between positively charged metallic ion and negatively charged sea of delocalised electrons is called metallic bond. It is stronger than ionic and covalent bond. Answer: (d)

angle between px and py is 90° and is minimum Answer: (b)

Electron configuration of NO according MO theory is Number of electrons in NO=15 <16 thus order of O2 is followedσ1s2, σ*1s2σ2s2, σ*2s2σ2pz2, π2px2=π2py2, π*2px1 Here Nb=10 and Na=5 ∴ B.O.=(10-5)/2=2.5 Answer:(c)

There is one pi-bond between two carbons rest of the bonds are σ Total σ bonds are 11 and one pi bondAnswer: (c)

ClO3- have sp3 hybridizationAnswer: (c)

Answer: (b)

Carbon tetrachloride does not ionize in the solution because it is a covalent. Carbon will not give Cl ion in the solution. No exchage between CCl4 and AgNO3 and AgNO3 ( Silver nitrate), no reaction take place. CCl4 is a covalent compound, therefore, it does not ionize to give Cl-. Hence it does not give white ppt of AgCl when treated with AgNO3 solution. There is no reaction to evolve NO2. CCl4 will forma separate layer as it is immiscible with water. Answer:(d)

The covalent bond in HCl Hδ+ - Clδ- is polary in nature. This is due to the appreciable electronegativivity difference of hydrogen and chlorine. Electronegativity difference is less than 1.5 thus it is polar covalent. Answer: (b)

BF2 has linear geometry bond angle is 180° NH3, H2O, CH4 has tetrahedral geometry. Lone pair -lone pair > lone-pair - bond pair > bond-bond pair CH4 bond angle is 109°28' no lone pair NH3 has 1 lone pair, H2O has two lone pair. Bond angle in H2O reduces from 109°28' to 104°5' as repulsion between two lone-pair reduces the bond-angle Answer: (b)

Answer: (a)

All options are fluorides and cation have same chargeAs cation size decreases there is a increases in lattice energyThus NaF has highest lattice energy Answer:(b)

Bond length ∝ (1/bond-order/ No. of bonds) Ethane have one bond Ethene have two bonds Ethynene have three bonds Benzene have three σ bonds and have three π bonds Bond length increase = Ethane > Ethene > Benzene > Ethyne. Ethyne have triple bond thus lowest bond lengthAnswer: (c)

Answer: (d)

Answer: (d)

Answer:(b)

BeF3- have sp2 hybridization. while remaining have sp3 hybridizationAnswer: (a)