Q.1.
Cotyledon of maize grain is called :- …[AIPMT-2016]
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a) plumule
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0%
b) coleorhiza
-
0%
c) coleoptile
-
0%
d) scutellum
Q.2.
Stems modified into flat green organs performing the functions of leaves are known as :- …[AIPMT-2016]
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a) Cladodes
-
0%
b) Phyllodes
-
0%
c) Phylloclades
-
0%
d) Scales
Q.3.
Among bitter gourd, mustard, brinjal, pumpkin, china rose, lupin, cucumber, sunnhemp, gram, guava, bean, chili, plum, petunia, tomato, rose, withania, potato, onion, aloe and tulip how many plants have hypogynous flower? [NEET 2013]
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0%
a) Six
-
0%
b) Ten
-
0%
c) Fifteen
-
0%
d) Eighteen
Q.4.
In China rose the flowers are …[NEET 2013]B22
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a) Actinomorphic, hypogynous with twisted aestivation
-
0%
b) Actinomorphic, epigynous with valvate aestivation
-
0%
c) Zygomorphic, hypogynous with imbricate aestivation
-
0%
d) Zygomorphic, epigynous with twisted aestivation
Q.5.
Seed coat is not thin, membranous in …[NEET 2013]
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a) Maize
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0%
b) Coconut
-
0%
c) Groundnut
-
0%
d) Gram
Q.6.
The term 'polyadelphous' is related to :- …[NEET 2016]
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a) Corolla
-
0%
b) Calyx
-
0%
c) Gynoecium
-
0%
d) Androecium
Q.7.
How many plants among Indigofera, Sesbania, Salvia, Allium, Aloe, mustard, groundnut, radish, gram and turnip have stamens with different lengths in their flowers ? …[NEET 2016]B22
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0%
a) Five
-
0%
b) Six
-
0%
c) Three
-
0%
d) Four
Q.8.
Radial symmetry is found in the flowers of :- …[NEET 2016]
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a) Pisum
-
0%
b) Cassia
-
0%
c) Brassica
-
0%
d) Trifolium
Q.9.
Free-central placentation is found in :- …[NEET 2016]B22
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0%
a) Brassica
-
0%
b) Citrus
-
0%
c) Dianthus
-
0%
d) Argemone
Q.10.
Coconut fruit is a ….[NEET- 2017]
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a) Drupe
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0%
b) Berry
-
0%
c) Nut
-
0%
d) Capsule
Q.11.
In Bougainvillea thorns are the modifications of ….[NEET- 2017]
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a) Stipules
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b) Adventitious root
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0%
c) Stem
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0%
d) Leaf
Q.12.
The morphological nature of the edible part of coconut is ….[NEET- 2017]
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a) Perisperm
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0%
b) Cotyledon
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0%
c) Endosperm
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0%
d) Pericarp
Q.13.
Axile placentation is present in : [ ReAIPMT 2015]
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a) Argemone
-
0%
b) Dianthus
-
0%
c) Lemon
-
0%
d) Pea
Q.14.
The wheat grain has an embryo with one large, shield-shaped cotyledon known as : [ ReAIPMT 2015]
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a) Coleoptile
-
0%
b) Epiblast
-
0%
c) Coleorrhiza
-
0%
d) Scutellum
Q.15.
exillary aestivation is characteristic of the family:
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a) Asteraceae
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b) Solanaceae
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0%
c) Brassicaceae
-
0%
d) Fabaceae
Q.16.
Among china rose, mustard, brinjal, potato, guava, cucumber, onion and tulip, how many plants have superior ovary? [ ReAIPMT 2015]
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0%
a) Four
-
0%
b) Five
-
0%
c) Six
-
0%
d) Three
Q.17.
Sweet potato is a modified … …[NEET 2018]
-
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a) Stem
-
0%
b) Adventitious root
-
0%
c) Tap root
-
0%
d) Rhizome
Q.18.
The plant parts which consist of two generations - one within the other (a) Pollen grains inside the anther (b) Germinated pollen grain with two male gametes (c) Seed inside the fruit (d) Embryo sac inside the ovule [NEET 2020]
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0%
a) (c) and (d)
-
0%
b) (a) and (d)
-
0%
c) (a) only
-
0%
d) (a), (b) and (c)
Q.19.
Placentation in which ovules develop on the inner wall of the ovary or in peripheral part, is ... [ NEET 2019]
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a) Basal
-
0%
b) Axile
-
0%
c) Parietal
-
0%
d) Free central
Explanation
Q.20.
Sweet potato is a modified ... ..[NEET 2018]
-
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a) Tap root
-
0%
b) Adventitious root
-
0%
c) Stem
-
0%
d) Rhizome
Q.21.
The main function(s) of root system is/are
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a) absorption of water and minerals from the soil
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b) storing reserve food material
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c) synthesis of plant growth regulators
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d) All of the above
Q.22.
In flower (X), the gynoecium occupies the highest position while the other parts are situated below it. The ovary in such flowers is said to be Y. Identify X and Y and select the correct option.
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a) X - Epigynous, Y - Inferior
-
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b) X - Perigynous, Y - Superior
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c) X - Hypogynous, Y - Superior
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d) X - Perigynous, Y - Half-inferior
Q.23.
Identify the inflorescence shown by the given figures A and B.
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a) A-Cymose, B-Racemose
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b) A-Racemose, B-Cymose
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c) A-Racemose, B-Racemose
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d) A-Cymose, B-Cymose
Q.24.
Match column I with column II and choose the correct option.
| Column-I | Column-II |
| A. Bud in the axil of leaf | I. Pitcher plant and Venus fly trap |
| B. Outer layer of seed coat | II. Cacti |
| C. Spines (modified leaves) | III. Testa |
| D. Leaves modified to catch insects | IV. Simple leaf |
| E. Fleshy leaves with stored food | V. Garlic and onion |
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a) A -I, B -II, C - III, D - IV, E- V
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b) A- V, B- IV, C- III, D - II, E - I
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c) A - IV, B - III, C - II, D - I, E - V
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d) A - IV, B - II, C - III, D - I, E - V
Q.25.
Statement-1 : Ginger has a prostrate-growing rhizome. Statement-2 : Shoot growth is not effected by gravity.
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a) Statement-1 and statement-2 are true and Statement-2 is a correct explanation for statement-1.
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b) Statement-1 and statement-2 are true but statement-2 is a correct explanation for statement-1.
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0%
c) Statement-1 is true and statement-2 is false.
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0%
d) Both the statements are false.
Q.26.
Which of the following statement (s) is/are not correct?Calyx and corolla are reproductive organs of a flower.Zygomorphic flower can be divided into two equal radial halves in any radial plane.Flowers without bracts are termed as abracteate.Parthenocarpic fruit is formed after fertilization of the ovary.In legumes, seed is non-endospermic.Radical buds develop on roots.
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a) (i) , (ii), (iii) and (iv)
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b) (i), (ii) and (v)
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c) (iii), (iv) and (vi)
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d) (iv), (v) and (i)
Q.27.
Which of the following statement(s) is/are correct about the fruit?Fruit is a mature or ripened ovary, developed before fertilization.It consists of a wall or pericarp and seeds.When pericarp is thick and fleshy, it is differentiated into outer mesocarp, middle epicarp and the inner endocarp.In mango and coconut, the fruit is known as a berry.
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a) Only (i)
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b) Both (ii) and (iii)
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c) Only (ii)
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d) All of these
Q.28.
Statement 1 : A simple leaf has undivided lamina. Statement 2 : Leaves showing pinnate and palmate venations have various type of incisions.
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a) Statement-1 and statement-2 are true and statement-2 is a correct explanation for statement -1.
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b) Statement -1 and statement -2 are true but statement-2 is not a correct explanation for statement-1.
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0%
c) Statement-1 is true and statement-2 is false.
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0%
d) Both the statements are false.
Q.29.
Which type of function is performed by the fleshy leaves of onion and garlic?
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a) Storage
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b) Reproduction
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c) Photosynthesis
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d) Protection
Q.30.
An underground stem in which food is stored in bulblet is:
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a) Solanum tuberosum.
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b) Allium cepa.
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0%
c) Allium sativum.
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0%
d) Amorphophallous.
Q.31.
The placentation in china rose, tomato and lemon is:
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a) Marginal.
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0%
b) Axile.
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0%
c) Parietal.
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0%
d) Free central.
Q.32.
A monocarpic plant is:
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a) Mangifera indica.
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b) Saccharum officinarium.
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0%
c) Bambusa.
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0%
d) Alnus.
Q.33.
In Australian acacia, which of the following part of the plant becomes green and synthesises food?
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a) Stem.
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b) Leaves.
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0%
c) Petiole.
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0%
d) Internodes.
Q.34.
The mature seeds of plants such as gram and peas, possess no endosperm, because
-
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a) these plants are not angiosperms.
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b) there is no double fertilization in them.
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0%
c) endosperm is not formed in them.
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0%
d) endosperm gets used up by the developing embryo during seed development.
Q.35.
Rearrange the following zones seen in the regions of root tip and choose the correct option. (A) Root hair zone (B) Zone of meristem (C) Root cap zone (D) Zone of maturation (E) Zone of elongation
-
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a) C, B, E, A, D
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0%
b) A, B, C, D, E
-
0%
c) D, E, A, C, B
-
0%
d) E, D, C, B, A
Q.36.
Identify the kind of phyllotaxy shown in the given figures A, B, and C.
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a) A-Alternate, B - Opposite, C - Whorled
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b) A- Whorled, B - Opposite, C -Alternate
-
0%
c) A-Alternate, B - Whorled, C - Opposite
-
0%
d) A-Whorled, B -Alternate, C - Opposite
Q.37.
Leaves of dicotyledonous plants possess _________ venation, while _________ venation is the characteristic of most monocotyledons.
-
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a) reticulate and parallel
-
0%
b) parallel and reticulate
-
0%
c) reticulate and perpendicular
-
0%
d) obliquely and parallel
Q.38.
hich one is a source of commercially important product Syzygium aromatticum?
-
0%
a) Flower bud
-
0%
b) Axillary bud
-
0%
c) Thalamus
-
0%
d) Peduncle
Q.39.
This floral formula represent:
-
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a) Tulip.
-
0%
b) Tobacco.
-
0%
c) Withania.
-
0%
d) Sunhemp.
Q.40.
Alstonia is an example of;
-
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a) Whorled phyllotaxy.
-
0%
b) Alternate phyllotaxy.
-
0%
c) Opposite superposed.
-
0%
d) Opposite decussate.
Q.41.
Which among the following is not a distinguishing character of Solanaceae?
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a) Bicarpellary, syncarpous ovary with axile placentation.
-
0%
b) Persistent calyx and epipetalous stamen.
-
0%
c) Diadelphous Androecium and zygomorphic flower.
-
0%
d) Oblique ovary and swollen placenta.
Q.42.
The roots of a turnip plant are swollen and fleshy because
-
0%
a) They store water.
-
0%
b) They are swollen to give extra strength to the root system
-
0%
c) They store food.
-
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d) None of the above.
Q.43.
Identify this plant modification and Select the correct option
-
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a) Sweet potato – simple tuberous root
-
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b) Dahlia – fasciculated tuberous root
-
0%
c) Asparagus - simple tuberous root
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d) Beet – tap root
Q.44.
Match list I with list II and select the correct answer using the codes given below the lists.
| List I | List II |
| P. Total stem parasite | I Loranthus |
| Q. Assimilatory root | II Pothos |
| R. clinging root | III Tinospora |
| S. partial parasite | IV cuscuta |
-
0%
a) P= IV ; Q = II; R = III ; S = I
-
0%
b) P= IV ; Q = III; R = II ; S = I
-
0%
c) P= II ; Q = III; R = I ; S = IV
-
0%
d) P= II ; Q = IV; R = III ; S = I
Q.45.
Which of the following is a wrong pairing?
-
0%
a) Raceme - Mustard
-
0%
b) spike - Achyranthus
-
0%
c) compound umbel - Onion
-
0%
d) spadix – musa
Q.46.
Modified stem of _______ protect the plant from grazing animal.
-
0%
a) Datura festuosa
-
0%
b) Aloe vera
-
0%
c) Gloriosa superba
-
0%
d) Carissa carandus
Q.47.
A composite or multiple fruit develops from :
-
0%
a) Polycarpellary ovary
-
0%
b) Bicarpellary and syncarpous ovary
-
0%
c) Apocarpous ovary
-
0%
d) Inflorescence
Q.48.
Aleurone layer of maize grain is specially rich in:
-
0%
a) Proteins.
-
0%
b) Starch.
-
0%
c) Lipids.
-
0%
d) Both B and C.
Q.49.
Identify the incorrect matching pair with regard to the edible part:
-
0%
a) Coconut – Endosperm.
-
0%
b) Papaya – Mesocarp.
-
0%
c) Mango – Epicarp.
-
0%
d) Apple – Fleshy thalamus.
Q.50.
The given figure shows the parts of mango and coconut. Choose the option which shows the correct labelling of A, B, C and D marked in the figures.
-
0%
a) A - Epicarp, B - Mesocarp, C - Seed, D - Endocarp
-
0%
b) A - Epicarp, B - Mesocarp, C - Ovule, D - Endocarp
-
0%
c) A - Epicarp, B - Mesocarp, C - Ovary, D - Endocarp
-
0%
d) A - Epicarp, B - Mesocarp, C - Embryo, D - Endocarp